Add a license.

[wordplay-cdsw-solutions] / solution_7.py

import scrabble


# Find the most valuable word in the dictionary using a double-loop. 


max_score = 0
max_word = ''
for word in scrabble.wordlist:
    score = 0
    for char in word:
        score = score + scrabble.scores[char]
    if score > max_score:
        max_word = word
        max_score = score

print max_score
print max_word