projects.mako.cc - wordplay-cdsw-solutions/blob - solution_9.py

   1 import scrabble
   2
   3 # Make a list of the highest scoring word that starts with each letter.
   4
   5 # This is a bit more advanced, but you already know how to do every single piece of this.
   6
   7 # This only returns 1 word with the given score.
   8
   9 expensive_word = {}
  10 expensive_word_score = {}
  11
  12 for word in scrabble.wordlist:
  13     first_letter = word[0]
  14     if first_letter not in expensive_word:
  15         expensive_word[first_letter] = ''
  16         expensive_word_score[first_letter] = 0
  17
  18     score = 0
  19     for char in word:
  20         score = score + scrabble.scores[char]
  21
  22     if expensive_word_score[first_letter] < score:
  23         expensive_word[first_letter] = word
  24         expensive_word_score[first_letter] = score
  25
  26
  27 for key in expensive_word:
  28         print "{key}: {word}, {score}".format(key=key, word=expensive_word[key], score=expensive_word_score[key])
  29
  30
  31