X-Git-Url: https://projects.mako.cc/source/wordplay-cdsw-solutions/blobdiff_plain/884ad8e21ea1ea9d1dd411b2a503d0dff4294c59..HEAD:/solution_5_advanced.py

diff --git a/solution_5_advanced.py b/solution_5_advanced.py
index aac8b19..202648b 100644
--- a/solution_5_advanced.py
+++ b/solution_5_advanced.py
@@ -1,23 +1,23 @@
 import scrabble
 
 
-# This is a solution to 5 that reuses the code in 1. 
-# Whenever we can, it's good to reuse code that we already have.
-# Next Saturday, we'll talk about defining functions, which is the way programmers
+# This is a solution to 5 that reuses the code in 1.  Whenever we can,
+# it's good to reuse code that we already have.  In a future session,
+# we'll talk about defining functions, which is the way programmers
 # re-use code.
 
 matching_words = []
 
-
 for word in scrabble.wordlist:
     if word[0] == 'a' and len(word) >= 9:
         matching_words.append(word)
 
 
-# Note that I use enumerate. You should look that up online to see what it does.
+# Note that I use enumerate. You can look up the enumerate function
+# online to see what it does. We're also using a new operating "%"
+# which is the modulo operator and which is more flexible than the
+# "bool" based version we used before.
+
 for i, word in enumerate(matching_words):
     if i % 2 == 0:
-	print word
-            
-
-
+        print(word)