major updates to the solutions
[wordplay-cdsw-solutions] / solution_9.py
index 1642ee8bf41f6b78dac7bc3033f5a83b102f879d..08ba7575756f0786f4c9d721891e7513eecea33b 100644 (file)
@@ -2,7 +2,8 @@ import scrabble
 
 # Make a list of the highest scoring word that starts with each letter.
 
-# This is a bit more advanced, but you already know how to do every single piece of this.
+# This is a bit more advanced, but you already know how to do every
+# single piece of this.
 
 # This only returns 1 word with the given score.
 
@@ -12,20 +13,16 @@ expensive_word_score = {}
 for word in scrabble.wordlist:
     first_letter = word[0]
     if first_letter not in expensive_word:
-       expensive_word[first_letter] = ''
-       expensive_word_score[first_letter] = 0
+        expensive_word[first_letter] = ''
+        expensive_word_score[first_letter] = 0
 
     score = 0
     for char in word:
         score = score + scrabble.scores[char]
 
     if expensive_word_score[first_letter] < score:
-       expensive_word[first_letter] = word
-       expensive_word_score[first_letter] = score
-
+        expensive_word[first_letter] = word
+        expensive_word_score[first_letter] = score
 
 for key in expensive_word:
-       print "{key}: {word}, {score}".format(key=key, word=expensive_word[key], score=expensive_word_score[key])
-         
-
-
+    print(key + ": " + expensive_word[key] + ", " + str(expensive_word_score[key]))

Benjamin Mako Hill || Want to submit a patch?